Why doesn't \n print out the Buffer?

[sleek latch]

`#include <stdio.h>

int main(int argc, char **argv) {

printf("Number: \n");
int number;
scanf("%d", &number);
printf("%d", number);
return 0;

}`
I thought that using \n forces the buffer to print "Number: " out. Why isn't this the case?

[bright torrent]

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[fallow dawn]

You can force to flush the buffer by using fflush(stdout)
'\n' is just a character, doesn't force C to actually print it yet

However it is interesting that you don't see the Number: output, it usually would appear or at least I don't really know why it wouldn't.
Anyway, try it with the fflush, that'll work for sure

[sleek latch]

It only showes up, when I enter a Number and then press enter.
But thx for your help

[fallow dawn]

#include <stdio.h>

int main(int argc, char **argv) {

    printf("Number: \n");
    fflush(stdout);
    int number;
    scanf("%d", &number);
    printf("%d", number);
    return 0;
}

There, that's how I meant it

Could you try that code and see if it works?

[sleek latch]

yes it works thx

[fallow dawn]

👍

[sleek latch]

!solved