Gross Template Syntax question

[remote geyser]

Hey folks, I have a function that looks like this:

template<typename R, class C, typename ... As>
constexpr static void TemplatedFunction(R(C::*funcPtr)(As...))

Is it possible to get TemplatedFunction to take an rvalue reference as an input? R(C::*funcPtr&&)(As...) and R(C::*funcPtr)(As...)&& do not seem to be doing the trick.

[warped edge]

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[river whale]

std::add_rvalue_reference ? I think so

[remote geyser]

Still unable to deduce the template argument from the function pointer I'm afraid

[vivid sundial]

why would you need to take a pointer to member function by reference? let alone by rvalue reference?

[jolly lodge]

^ Member references are constants. No need for reference or r-value as they won't change at runtime. The pointer semantics is more to differentiate from calls/references to the value.

Although actually if the reference would be coming from a variable, that variable can change at runtime so taking a pointer/reference to that could make sense to use the updated value down the line, however I struggle to see what uses-case that would have. But also no point in r-value as member references are just numbers at runtime and not structures.