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can't call a function outside a function
IOW, in global scope what one can do is very limited, and malloc(...) call isn2t allowed
this is my guess as to what's happenning without the light of a proper error message, sorry
why are we doing typedef struct Node* NodePtr;?
Node* nodePtr = malloc(...)
but it's not a struct, is it?
it has no data
why would it be a struct?
no.
is it a struct? does it contain data?
riiight
if you can share the error message, i can guess something else because it works with the information you provided
typedef is valid C code even though questionable practice
questionable because it hides the type is a Pointer
even though the name literally has Ptr
you need to include a header
that has the declaration of the function malloc
which is the stdlib header
don't get me wrong but if you shared this warning in the original post, we would have spared a waste of time from both ends
you and people here
the compiler is being soft and proceeds to compile anyway
it's a "warning" as it says, not a fatal error
but that's not to be relied on at all
np
I wish the C compiler would not assume "a function returning an int".
Just error out and force me to fix my stupid mistake.
Otherwise I am just chasing my tail.
@surreal crystal Has your question been resolved? If so, type !solved :)
@surreal crystal
Please don't delete forum posts. They can be helpful to refer to later and other members can learn from them. In the future you can use !solved to close a post and mark a post as solved.