string concatenation

[zealous cypress]

Why the warning?

[idle cloak]

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@zealous cypress

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[empty axle]

string2 is a const char*, q is not.

[zealous cypress]

so i must either remove const from string2 or use string2 as a pointer itself?

[fresh phoenix]

q can be a const pointer

You only write to *p so only it must be non-const

[empty axle]

You'd have to remove const, you've declared string2 as const meaning you can't increment or decrement it

[fresh phoenix]

char const *q = string2;```

[fresh phoenix]

Not true

The const applies to the data that string2 points at

You can increment the pointer

[empty axle]

And not the pointer?

[zealous cypress]

I understand now, thank you!

[fresh phoenix]

That would be char *const

[empty axle]

Ohhhhh gotcha, my bad! 🫡

[fresh phoenix]

Np

there's a nice trick about readability

instead of const char * flip the order of the const and char: char const *

[zealous cypress]

one makes array constant and another makes pointer constant

[fresh phoenix]

the meaning is exactly the same, but now it's readable from right to left

follow these from right to left and see what i mean:

// pointer to char
char *p1;

// pointer to const char
char const *p2;

// const pointer to char
char *const p3;

// const pointer to const char
char const *const p4;```

char const * const p4; /*
^    ^     ^ ^          *
^    ^     ^ const      *
^    ^     ^            *
^    ^     pointer to   *
^    const              *
^                       *
char                    *
*************************/

and so on

C's type syntax is kinda wonky, this is one trick that can make it just a little more bearable

[idle cloak]

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