Argc and Argv

[edgy mica]

Can someone explain to me how to use argc and argv to make command line wait until the user will type something, and then do the code, call functions that I want to be called after the specific string like "-i" or "graph"?

Here's the code

int main(int argc, char* argv[]) {
bool printTree = false; // Flaga określająca, czy drzewo ma być wypisane
if (std::strcmp(argv[0], "-i") == 0) {
printTree = true;
return 0;
}

if (printTree) {
    Wezel* korzen = nullptr;

    for (int i = 1; i < argc; ++i) {
        if (std::isdigit(argv[i][0])) {
            int wartosc = std::stoi(argv[i]);
            wstaw(korzen, wartosc);
        }
    }

    std::cout << "Drzewo Red-Black:" << std::endl;
    inorder(korzen);
}

return 0;

}

[gaunt gate]

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[primal bough]

i don't understand the question

argc and argv have nothing to do with "making the command line wait"

[edgy mica]

well, basically i have to wait until the user prompt "-i" and then my code has to be ran, but it can't be done with cin

it's about command line arguments

[primal bough]

command line arguments are defined when the user launches your program

before your program even begins to run

you don't need to wait for them

by the time main is called, they are all already there

[edgy mica]

good to know
so is there any way to make it work without using 'cin'?
should i define the command line argument as "-i" and then wait until user will type string equal to this?

[primal bough]

no, command line arguments are passed in argc and argv

not cin

you get an array of all the arguments you're given

argc is the number of arguments

argv is the array of argument values

argument count
argument value

[edgy mica]

understandable,

[primal bough]

do note that the first entry in argv is generally the name of the executable

the actual arguments start at index 1, not 0

[edgy mica]

got it

thanks for help