how to deal with integer overflow on arrays part 2 | Together C & C++ | Page 1

well i showed a code recently but couldn't find that topic i created. Who made just use arrays to deal with printing beyond the value of an integer, the special case is when i wanna print a big binary number out of a result of a octal to binary convertion, see the code bellow:

#include <iostream>
#include <cmath>

using namespace std;

long long convertOctalToBinary(int);
int main()
{
    int octalNumber;

    cout << "Enter an octal number: ";
    cin >> octalNumber;

    cout << octalNumber << " in octal = " << convertOctalToBinary(octalNumber) << " in binary";

    return 0;
}

long long convertOctalToBinary(int octalNumber)
{
    int decimalNumber = 0, i = 0;
    long long binaryNumber = 0;

    while(octalNumber > 0)
    {
        decimalNumber += (octalNumber%10) * pow(8,i);
        ++i;
        octalNumber/=10;
    }

    i = 1;
    cout << "decimal is: " << decimalNumber << endl;

    while (decimalNumber > 0)
    {
        binaryNumber += (decimalNumber % 2) * i;
        decimalNumber /= 2;
        i *= 10;
    }

    return binaryNumber;
}

#how to deal with integer overflow on arrays part 2