#include <stdio.h>
int main()
{
int numbers[100];
for(int i = 0; i < numbers; i++)
{
scanf("%d", &numbers);
}
printf("%d", numbers);
}
Why do i recieve
#Arrays
mystic turtle
river stumpBOT
mystic turtle
oh wait i think i might know why
silent pecan
That's not how you get an array's length.
mystic turtle
Is it because numbers isn't a defined integer?
silent pecan
You are having an integer array, not a single integer.
mystic turtle
I'm not entirely sure how to acomplish this
basically the last value in the input indicates the position in the array that is made
wide cargo
Is it because numbers isn't a defined integer?
numbers, when used in a comparison like this, decays to a pointer, so the comparison could look like so:
i < 0xFA78350
```if the `numbers` array starts at `0xFA78350`, or it could be
```c
i < 0xA8730
```if the `numbers` array starts at `0xA8730`Or it could be anything else
mystic turtle
Ohh
wide cargo
But the main problem here is that you're comparing an integer and a pointer
mystic turtle
#include <stdio.h>
int main()
{
int numbers[100];
for (int i = 0; i < numbers; i++)
{
scanf("%d", numbers);
}
printf(" %d", numbers);
}
But how do i store scans into an array?
or sorry
how do i decide when the loop stops?
wide cargo
If you want to get the length of an array you can use this:
#define arr_len(arr) (sizeof (arr) / sizeof (*arr))
If you want to get the length of a pointer there is no way to do so, you need to remember that size yourself
mystic turtle
https://gyazo.com/60198b46ad0fe2dae78ae0e5e685c526
But basically i want the first Int to represent how long the loop will be
meanwhile the last integer the position in the array to print
mystic turtle
WIll do
If i for example do somethig like this c for (int i = 0; i < numbers[0]; i++) { scanf("%d", numbers[i]); }
Does the loop even start?
or does a for loop require the condition to be true to start the loop?
onyx zephyr
```c
#include <stdio.h>
int main()
{
int numbers[100];
for(int i = 0; i...
you're comparing the array with a number
onyx zephyr
If i for example do somethig like this ```c
for (int i = 0; i < numbers[0]; ...
that checking if i is less than the first element in numbers, which isn't what you want
mystic turtle
But will the loop start even if the condition isn't met?
onyx zephyr
#include <stdio.h>
int main()
{
int numbers[100];
for(int i = 0; i < numbers[0]; i++)
{
scanf("%d", &numbers);
}
printf("%d", numbers);
}
what value do you think numbers[0] has on the first iteration?
mystic turtle
It will be empty
onyx zephyr
it's going to be a random value
mystic turtle
as numbers[0] doesn't exist until the scanf happens
Yeah sorry, an arbitrary number
onyx zephyr
do for(int i = 0; i < 100; i++)
mystic turtle
Yeah but that wont work either
onyx zephyr
secondly, scanf("%d", &numbers); is not correct
mystic turtle
i dont want the user to input 100 integers
it should be at most 100 integers
that's why i set the Array to 100
The first integer in the scanf will dictate how many integers there will be
onyx zephyr
it should be at most 100 integers
scanf will tell you when a number is not inputted
you can exit the loop in that case
onyx zephyr
scanf will return the number of items in the format string it successfully read, or a negative value on i/o error
onyx zephyr
with an if condition?
yeah, for example
if(scanf("%d", numbers+i) != 1)
{
//error
}
also I presume you want to write to the element with offset i from the start of the array
mystic turtle
Hmm i don't think doing it that way will work
onyx zephyr
what seems to be wrong?
mystic turtle
I just want to scan an array of Integers.
And then i will print the n:th integer based on the last integer in the array.
My main problem is having the loop stop
I want the loop to stop based on the first integer input
#include <stdio.h>
int main()
{
int numbers[100];
int x = 0;
scanf("%d", &x);
for (int i = 0; i < x + 1; i++)
{
scanf(" %d", &numbers[i]);
}
printf("%d\n", numbers[numbers[x]]); // the last integer in the array will decide which array position to print.
}
Okay i think I'm close
i am sure that i am scanning correclty now
Now i just need a tiny hint on how to print correctly :c
Okay i got it to work, i just needed to think out loud (type)
wide cargo
If i for example do somethig like this ```c
for (int i = 0; i < numbers[0]; ...
You really didn't read the article I linked you, did you?
wide cargo
Then how could you initially do it so wrong, when it's written there so clearly?
mystic turtle
!solved