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#Input an integer n, and output the estimated π values of the series at the nth item.
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vivid kiln
Which part are you stuck on?
pseudo sonnet
#include <iostream>
using namespace std;
int main() {
int num;
int a,a2;
int b=1;
int c=1;
cout<< "Input a number: ";
cin >> num;
for (int num2=1;num2<=num;num2++){
c*=num2;
if (a%2==1){
a2=a+b;
}
else {
a2=a-b;
}
}
cout << c;
return 0;
}
the math part
i will need to add 2n-1 into the loop right
vivid kiln
Your naming is confusing. Where is your pi variable? What are a and a2 and b and c?
I understand num.
Apparently c is your pi because you print it out. The problem is that c is an int which means integer which means no comma and no digits after the comma which is not suitable to hold pi.
vivid kiln
Better double
I don't understand c*=num2; at all. Where did that multiplication come from? Both formulas use sums only, you never multiply your pi estimate with anything.
pseudo sonnet
this is about using for to write down the math equation
pseudo sonnet
leibniz
vivid kiln
Ok. I see a 4 in every term and then it gets divided by something. Where is the 4 in your code?
tacit garden
Holy cow Toeger going deep