drifting owl
#define SIZE 9
void idk(void) {
// Initialising array
int random_array[SIZE][SIZE] = {};
for (int i = 0; i < SIZE; i ++) {
for (int j = 0; j < SIZE; j ++) {
random_array[i][j] = 0;
}
}
random_array[3][4] = 1
for (int i = 0; i < SIZE; i ++) {
for (int j = 0; j < SIZE; j ++) {
// This will always be true due to the nature of
// whats inside
// Thus bringing 1 to the end of row before crashing as
// invalid array index will be accessed
if (random_array[i][j] == 1) {
random_array[i][j] = 0;
random_array[i][j + 1] = 1;
}
}
}
}
- If there are any elements == 1 in the array I need to move them across the row one by one
I've already got if statements to make sure these don't go out of bounds, the above is just a rough example - If there are two or more elements == 1 in the 2d array I need them to move in order, from left to right
The code on top won't do this one by one:
(every time func is called, all elements == 1 should move to the right by one space)
The only 'solution' I can think of is reversing the way in which the rows loop:
for (int j = 8; j >= 0; j --) {
}
but this won't be true to the second condition, it will move the elements in order of: right to left
I've been racking my brains but can't come up with a solution
anyone have any ideas?
summer vapor