returning wrong output

[visual tartan]

#include <bits/stdc++.h>
#include <iostream>

using namespace std;

int main(){
int i;
int a[3];
int b[3];
for (i=0; i<=2; i++ ) {
cin>>a[i];
cin>>b[i];
}
int q = 0;
int w = 0;
for (i=0; i<=2; i++ ) {

if (a[i]>b[i]) {
   q++;
}
else if (a[i]<b[i]) {
   w++;
}
else {
q=q;
w=w;
}
}
cout<<q<<" "<<w;
return 0;

}

[scenic turtle]

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[boreal zenith]

Not only a VLA.
But a VLA using an uninitialised length variable.

I think you were meant to declare them as:

int a[3];
int b[3];

[visual tartan]

still wrong answer

[boreal zenith]

for (i=0; i<=2; i++ ) {
    cin>>a[i];
    cin>>b[i];
}

You are alternating between a and b here

If you enter on the command line "5 6 7" then:
a[0] becomes 5
b[0] becomes 6
a [1] becomes 7

You should simplify this to:

cin >> a[0] >> a[1] >> a[2];
cin >> b[0] >> b[1] >> b[2];

Or you can loop twice. First one for just a.
Second time for just b.

[visual tartan]

Thanks @boreal zenith

!solved

[scenic turtle]

Thank you and let us know if you have any more questions!

[SOLVED] returning wrong output

[boreal zenith]

Suggestion (points for style):
rename variable q to alice.
rename variable w to bob.

Up to you.

And this:

else {
    q=q;
    w=w;
}

Is pointless code.
You could just delete this without worry.

[visual tartan]

okk buddy

actually i am still learning basics

i thought it is necessary to write else statement in a if else loop

thank you for helping

[visual tartan]

but i was silly....now i know that

[boreal zenith]

if (x)
{
}
else if (y)
{
}

Is perfectly fine.

[visual tartan]