Going from python to Rust. How would I do this function?

[worthy epoch]

Here is the function in python:

list1 = ["one", "two", "three", "four"]
list2 = ["three", "four"]
def tester():
    for item in list1:
        if item not in list2:
            print(f"found! {item}")

Im just sorting through the list and finding the difference between the two. I'm trying to write this in rust for the speed

fn test() {
    let mut list1 = vec!("one", "two", "three", "four");
    let mut list2 = vec!("three", "four");
    for item in list1 {
        if item not in list2 {  // This line is not happy
            println!("{}", item)
        }
    }
}

I tried to do a similar thing In rust. I am wanting it to print out "one" & "two".
The problem that im having is that there seems to be no 'not' operator and 'in <iterable>' seems to not work. Tried looking at the docs and didn't see any mention of a 'not' type operator. Any help would be appreciated

[somber tartan]

thats indeed not a thing, there are no magic keywords like that

but Rust does have another handy tool, iterators

in this case, we can just use !list2.contains(item)

instead of using cursed keywords, we use methods, in this case, check out the methods on Vec<T> (and associated slice &[T])