JavaFX intersection of nodes | Together Java | Page 1

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<@&987246487241105418> please have a look, thanks.

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TJ-Bot

How can I check intersection of 2 nodes according to scene location, nodes are out of pane

To check for the intersection of two nodes in JavaFX, you can use the method localToScene to convert the coordinates of the nodes to scene coordinates. Then, you can use the intersects method to check if the bounds of the nodes intersect.

Here is an example code snippet to demonstrate this:

// Assuming node1 and node2 are the two nodes you want to check for intersection
Bounds bounds1 = node1.localToScene(node1.getBoundsInLocal());
Bounds bounds2 = node2.localToScene(node2.getBoundsInLocal());

if (bounds1.intersects(bounds2)) {
    System.out.println("Nodes intersect!");
} else {
    System.out.println("Nodes do not intersect.");
}

This code snippet first converts the local bounds of each node to scene coordinates using localToScene. Then, it checks if the bounds of the two nodes intersect using the intersects method.

If your nodes are out of a pane, you will need to ensure that they are added to a scene before performing this check. If they are not added to a scene, you will need to calculate their positions relative to each other manually before checking for intersection.

By following these steps, you can easily check for intersection between two nodes in JavaFX based on their scene locations.

#JavaFX intersection of nodes