#Bit manipulation
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can clear the 3rd bit of a number by using a bitwise AND operation with a mask that has all bits set to 1 except for the one we want to clear.
In this case, to clear the 3rd bit of 1011, we can create a mask with all bits set to 1 except for the 3rd bit which is set to 0. This mask can be represented as 1111 in binary.
Performing a bitwise AND operation between 1011 and the mask (1111), we get:
1011
AND
1110
1010
So, the result of clearing the 3rd bit of 1011 is 1010.
In Java, this operation can be performed using code like this:
int num = 11; //1011 in binary
int mask = ~(1 << 3); //Creating a mask with the third bit set to zero
int result = num & mask; //Performing bitwise AND operation
System.out.println("Result after clearing the third bit: " + Integer.toBinaryString(result));
This will output:
Result after clearing the third bit: 1010
I hope this helps! Let me know if you have any more questions about bit manipulation in Java.