#Pls help me🙏

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grim ember
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Find BAD

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Then by the sum angles of ABCD = 360 deduce x

celest wing
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I would do it this way: ||move the triangle ADC in a way that red segments coincide and A->E. You get an isosceles triangle EAC with its angles expressed in terms of x. Then reflect A->F with respect to EB. You get a cyclic quadrilateral EBFC. Since it is symmetric, we have BC=EF=AE=AC. Thus, ABC is isosceles and 7x=180°-11x, which implies x=10°.||