#GENERAL MATH: EQUATIONS
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Write down the terms in $f(x)$ and $g(x)$ which have a $x^3$ term on expanding, these are the $(x+1)^3$ and $(x+1)^4$ terms, do the same for $g(x)$ subtract them you get $(x+1)^3(a_3 - b_3)$ expanding we see that the coefficient of $x^3$ is $a_3 -b_3$.
desshshsi
its actually a_3 - b_3 - 4
@sour roost os the answer (-4)
thats a good question
first find the polynomial f(x) - g(x) :
it would be a polynomial of 3 degree
since its given then f(x) - g(x) is not zero for all x's
the coeffiecient of x^3 in it must be zero since odd degree polynomials have their range as real
and the coefficient of x^3 is a_3 - b_3 in it