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[tame lark]

I cant figure this one out lol

website: https://neal.fun/not-a-robot/

[lapis oasis]

$\frac{5}{8}<2=2!=\frac{4\cdot3}{6}<\frac{4\pi}{6}<\log_{4}\left(22\right)<2.5<\sqrt{8}<3<20=\int_{3}^{7}xdx<22=\sum_{i=4}^{7}i<32=2^{5}<e^{5}$

[torpid storm]

BlockLayer2000

[lapis oasis]

$\log_{4}\left(22\right)<2.5$ since $22<4^{2.5}=32$

[torpid storm]

BlockLayer2000

[lapis oasis]

$2.5<\sqrt{8}$ since $2.5^2=6.25<8$

[torpid storm]

BlockLayer2000

[lapis oasis]

I estimated that $\frac{4\pi}{6}<\log_{4}\left(22\right)$

[torpid storm]

BlockLayer2000

[lapis oasis]

Also $2<e\implies2^5<e^5$

[torpid storm]

BlockLayer2000

[lapis oasis]

'Course, none of those are squares