#geometric series help
5 messages · Page 1 of 1 (latest)
You can call the series Sn which give you.
Sn = 1 + a + a^2 + … a^n
You can then say
a*Sn = a + a^2 + a^3 + … a^(n + 1)
Subtract both you will get.
Sn - a*Sn = 1 - a^(n + 1)
(1 - a)Sn = 1 - a^(n + 1)
Sn = [ 1 - a^(n + 1) ] / [ 1 - a ]
Since |a| < 1, limit of Sn to infinity will get you.
Sn = 1 / ( 1 - a)
Because a^(n + 1) will become 0.
So the series converge if |a| < 1.
For |a| not equal to one, you can plug in the series and see it start to oscillate and grow instead of converge for a < -1 so therefore the series diverge.
a > 1 the series goes to inf
It better to show both negative and positive side and describe the different. If other people reading this doc then don’t use - because I confused it for negative sign.