#Proof by contradiction

19 messages · Page 1 of 1 (latest)

rotund harbor
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Can someone explain how proof by contradiction works please. In the images, we are trying to prove that squareroot of 2 is irrational.

I have a question based on the workings. How can we assume that a is even? Is it because 2 * b^2 is always even and so must be a^2. Now if the square of a number is even, does that mean that the squareroot of that number is also even?

Similarly, if 2 divides a, this mean 4 divides a^2?

plain knollBOT
urban valve
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we are not assuming that a is even

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we start by assuming that sqrt(2) is rational

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and using that assumption to show that a has to be even

obsidian summit
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the basic idea of a proof by contradiction is to assume the opposite of our statement is true, but then showing said assumption leads to a logical contradiction down the road. this contradiction shows that our assumption was impossible, so the original statement must be true.

rotund harbor
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yep I see, can we say the following:

2 * b^2 is always even, this mean a^2 is also even and so must be a?

In general if the square of a number is even, does that mean that the squareroot of that number is also even?

obsidian summit
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of course. squaring a number is multiplying it by itself. consider the two cases of squaring an even and squaring an odd number separately. which gives you an even number?

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try it!

rotund harbor
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oh ok right

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4^2 = 16 which is even but 3^2 = 9 which is odd

obsidian summit
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you can even prove this algebraically

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an even number is 2k, and an odd number is 2j + 1 for some natural j, k

rotund harbor
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yep, if we pick up some numbers 2k will always be even and 2j + 1 will always be odd

obsidian summit
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squaring an even number gives us 4k^2 = 2(2k)(k), and since k is a natural and there's a constant factor of 2, this must be even

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likewise, squaring an odd number gives us (2j+1)^2 = 4j ^2 + 4j + 1 = 2(2j^2 + 2j) + 1, and since j is a natural, the expression inside the brackets must be natural as well, so we can say it's some natural m
then 2(2j^2 + 2j) + 1 = 2m + 1 and we get another odd

rotund harbor
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yeah I see make sense now, thanks !!

obsidian summit
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anything you stilll wanna know about your original question?

rotund harbor
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nope all good for now, thanks !