#Diffeomorphisms
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@sleek quiver
tanx=sinx .(1/cosx)
since composition of two C^inf functions are also C^inf
Let g=1/x and f=cosx then gf(x)=1/cosx is also C^inf
Now product of two C^inf functions is also C^inf
So sinx.gf(x) is also C^inf
Oh that makes sense 😅, I was thinking in taking its derivatives