Help with Alg 2 summer class understanding question + how to solve.

[versed pecan]

Can you post a clear screenshot of the question (inserted directly here) rather than posting an attachment?

[ebon wyvern]

sorry

[versed pecan]

May we see any attempt you have made?

Do you know the Laws of Exponents?

[ebon wyvern]

I do, and the answers with the X's were my attempt

[unkempt shuttle]

Did you try multiplying the product in the braces and simplifying the expression on the right side?

[versed pecan]

Consider two parts: 1st Part (multiplication) and 2nd Part (division)

1st Part: Inside Parenthesis: what is $\dfrac{2}{3} + \dfrac{1}{2}$?

[thorny fiber]

The Mathematics Guy

[empty beacon]

let's break this part by part
the first part: (x^2/3 . x^1/2)
because the bases are the same(x)
you can add the exponents
2/3 + 1/2
you'll get ||7/6||
then when you apply the ^3
it will be: (x^||7/6||)^3 = x^(3 * ||7/6||) = x^||21/6||

and then the right part:
because you are dividing them, instead of adding the exponent, you subtract them:
x^5/2 / x^3/2 = ||x^3/3 = x^1 = x||

now you multiply the right part and the left part:
||x^21/6 . (x^1 = x^6/6) = x^27/6 = x^9/2||
in the radical form of:||√x^9||