Ok so I found a pretty weird thing i need help to understand.

[pale escarp]

You have something different from (-3+2^((x+2)/2))*log2 (16) in geogebra

[stone blaze]

i know, but it is actually the same thing. log2 (16)=4 and 2^(2+x)/x is 2*2^(2/x)

realized i wrote it wrong in the original question, it is 2^((x+2)/x)

the one in the graph calculator is the correct one

[pale escarp]

Then 3 is not a solution

[stone blaze]

well the teacher marked it as correct

[pale escarp]

Just plug it into the equation

[stone blaze]

well yeah thats what i was asking

why do we get this solution if we solve the equation the traditional way, but the solutions dont work

[pale escarp]

So, it is either the equation is wrong or the teachers remarks

[stone blaze]

if you want i can show you the solution steps if you want

but it will take a second as i have to rewrite it on paper

ok it appears i am a little bit of an idiot and cant write properly.

i managed to type the equation wrong for the 3rd time

[pale escarp]

If you got 3 as an answer and the equation was as you corrected then there must be a mistake in the solution

[stone blaze]

Ok so im so sorry but now it apparently shows the 2 intersections in geogebra. It was 2^((x+3)/2.)