How can I solve this Bernoulli differential equation?

[lyric granite]

(2xy - x^2y^2)dx + (1+x^2)dy = 0

[sweet mortar]

First - rewrite as:
M dx + N dy = 0

Then check if it's exact - it's exact if:
∂M/∂y = ∂N/∂x

Then rearrange for dy/dx

it's a bernoulli equation so it has the form:
dy/dx + P(x)y = Q(x) y^n

let v = y^-1 for the bernoulli substitution

sub in with

dv/dx = (-y^-2)(dy/dx)

then simplify

then find the integrating factor e^ integral(-P(x) dx)

multiply through by the integrating factor, then integrate both sides

then just simplify and solve for v, and then once you have v you can find y

since v= 1/y

sorry it's vague, that's the general process for bernoulli equations with a bit of specific info for ur equation

@lyric granite if you have problems ill be back later tn just ping me

[lyric granite]

Thanks I could solve it