Let R be the constraining reaction, R_x,R_z its components along x,z, let P be the gravitational force, let θ be the angle formed between the tangent to the parabola and the x-axis, I reasoned as follows: let's impose the equilibrium condition R_x = F and R_z = P,
since R_x = R sinθ, R_z = R cosθ and deriving (in x) the parabola and knowing tanθ=z' we get x=2l therefore z = l/2, which are the coordinates of the point of tangency, that is A. This is correct.
Ah also it is easily seen with some calculations that the moment of the external forces with respect to the pole A is always 0.
Now I have no idea how to find C, does anyone know how to do it?
#Coordinate of a point in a mechanics exam exercise
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