#find lengths and deducing (sin cos theta)

7 messages · Page 1 of 1 (latest)

rigid talonBOT
sonic sapphire
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3b1:
sin2t = PN/l
2sint = 2PN/AP = 2PN/(2*AM) ( as AP = AM + MP and AM = MP) = PN/AM
So sin2t/2sint = PN/l/PN/AM = AM/l (eqn 1)
In triangle AMO, cos t = AM/l = eqn 1 = sin2t/2sint

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Rest are similar too

tranquil quarry
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thx but

sonic sapphire
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Post yer solution

fossil coyote
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Done?

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!done