#geometry help
29 messages · Page 1 of 1 (latest)
@warped oriole In this case, h is the height of the parallelograms (with the base being the shorter side of the parralelograms). You know both side lengths of the parallelogram, what's a theorem you could use to find h?
Not allowed to use the Pythagorean Theorem?
Who doenst allow the pythagorean theorem bro wha
Oh boy, this is stupid.
So what you wanna look at is the diagonal of the entire thing. Can you say something about it's length?
And what does that length imply?
Can you find a different shape in the entire object (including the center) with the same geometric features?
And finally, can you choose it in such a way that it includes h?
@warped oriole I'd draw you a picture of what I mean, but I'll have to search some paper first. ||ain't much of that on trains||
Use paralleogram area
The formula for the paralleogram area is base*height
The areas of all the paralleograms in the figure are equal
Find the area of one of the four identical paralleograms
Then find the perpendicular height of the base of length 4
And thats h
The perpendicular height of the paralleogram at the base 6 is 2 right?
So then what is the perpendicular height at the base 4
The area of the paralleogram = base*height
Yes
So first you find the area of the paralleogram which is?
Mhm
And that's h
Ok
Just because all the side lengths are equal doesn't mean it's a square
I think you mean a rhombus