I have a test to do tomorrow help | Mathematics | Page 1

midnight sinew Aug 5, 2024, 1:23 PM

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I BADLY need help with this since I can't understand :(

I already have the answers I just need someone to explain how each and one of them works

peak hedgeBOT Aug 5, 2024, 1:23 PM

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hoary stump Aug 5, 2024, 1:28 PM

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for (1) and (2), you can find 4x/3 - 3 as like your teacher wrote, there are " no restrictions"

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for (3), sqrt(x) is only defined for x>=0

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so in 3, you had sqrt(-y + 9), using what i said earlier, -y + 9 >= 0 and solve for y

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in (4), denominators cannot be 0 since you cant divide by 0

#I have a test to do tomorrow help