help | Mathematics | Page 1

woven sigilBOT Jul 18, 2024, 4:21 AM

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pseudo ether Jul 18, 2024, 4:23 AM

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😅

keen bone Jul 18, 2024, 4:27 AM

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To solve this you need to name your own variables, and be specific on what you want to find. Using the information given in the problem express mathematically the situation and the goal. Then you can work from there.

pseudo ether Jul 18, 2024, 4:40 AM

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let x,y & z the numbers, y is the second number
(i) y=2x
(ii) y=3z

x+y+z/3 = 44
using y=3z

z=y/3=2x/3

3x+2x/3=132

9x+2x=396

11x=396

x=396/11
(y=2x)

y=2*36= 72

so the biggest number would be y

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is this right?

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🙂

keen bone Jul 18, 2024, 4:42 AM

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yes, and clearly y should be the biggest of them.

pseudo ether Jul 18, 2024, 4:43 AM

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ik that it's not detailed but it's ok.

keen bone Jul 18, 2024, 4:44 AM

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looks good, mostly that some parts are unjustified (but correct), and the answer is not explicitly given, but yeah, if that's required you can fill in the blanks.

#help