quadratic equations y²+2y+12=0

[vapid jasper]

How do I solve this I'm stuck

[dark adder]

Use the quadratic formula

[vapid jasper]

Which one?

[dark adder]

what do you mean by which one

[vapid jasper]

I forgot the formula💀

[dark adder]

where in this case x = y

[vapid jasper]

Oh yeah thank you so much

[dark adder]

ay^2 + by + c

[vapid jasper]

U still here?

I made a mistake in the question

[dark adder]

mhm

oh

[vapid jasper]

The question is y²+2y+12

I need to do middle term

[dark adder]

What do you mean by middle term

2y?

[vapid jasper]

Ye

[dark adder]

What do you need to do with it

[vapid jasper]

Y²+2y+12÷y -y-2=15

[dark adder]

wait so do you mean $\frac{y^2 + 2y + 12}{y^2 - y - 1} = 15$

[ebon arrow]

Potatomonke

[vapid jasper]

Nah I meant the top part stays the same but the bottom only has y and -y-1 is in the side

[dark adder]

oh

so $\frac{y^2 + 2y + 12}{y} - y - 1 = 15$

[ebon arrow]

Potatomonke

[vapid jasper]

Yes

This is it

[dark adder]

ok so simplify it first

you get y + 2 + 12/y - y - 1 = 15

then just keep simplifying

y - y + 2 - 1 + 12/y = 15

1 + 12/y = 15

12/y = 14

[vapid jasper]

Thank you so much

[dark adder]

y = 12/14

y = 6/7