#topic name: conic section
6 messages · Page 1 of 1 (latest)
for the first one, number 28 its d the correct
because if you put x=0 and y=3 in equation its the solution of equation
The center of the circle is the point A(1,2) the normal lines have to have this point, so point A is solution only for first equation
X²+y²-4x-2y+2=0 , x²-4x+4-4+y²-2y+1-1+2=0 ,( x-2)²+(y-1)²=3. Center of circle is (2,1) that is median of diameter. (2+X)/2=2 and( 3+Y)/2=1. X=2 and y=-1 other point extrem of diameter is (2,-1)