#Poisson Distribution
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Your answer is right, exact one is of binominal distribution, and it can be approximated by poisson distribution with lambda=50*0.01
Exact answer=1-pro(num of AB-=0)-pro(num=1)
which can be approximated as 1-poission(lambda=0.5, k=0)-poission(lambda=0.5, k=1)
Sure
Sure
in practical case, lambda shows the average of arrivals in unit time.
You should firstly understand what poission distribution means. It is of counting numbers of happenings(arrivals, erros, requests to server, ...) in unit time.
Poission is absolutely not related to attempt. Binormial dist is.
In the above problem, the knowledge is about the approximation of BI with Po(lambda)
lol, n is for Bi, lambda is for Po. So you see now?
No problem