integration inverse tan

[limpid rampart]

Unless 1/2lne^2x is equal to arctan?

[winter anchor]

u substitution works

let u = e^x

then the integrand becomes u/(1+u^2)

du = e^x dx --> dx = du / e^x = du / u

so the integral becomes u / (1 + u^2) * du / u

the u and 1/u cancel and you get the integral of 1/(1+u^2) du

which becomes arctan(u)

[limpid rampart]

oh shit

your right

thats so cool how that still wroks lol

I did my u sub very wrong

tysm!