#simple big o question
19 messages · Page 1 of 1 (latest)
yes
yes
yes
General rule (for some constant $m > 1$): $\log n < \sqrt[m]{n} < n < n^m < m^n < n!$
SWR
Always ignore lesser terms
That's the magic of Big O. You only care about the dominating factor
yes
yes
hmmmm
good question
I think it becomes O(n!)
let me review my book
it gives formal definition of big O
It would be O(n! n)
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