#can someone explain how to answer this question fully

22 messages · Page 1 of 1 (latest)

rich mantle
grand oakBOT
gilded hinge
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For the first one you can rewrite the sum of trig expressions as a single expression as shown in the image.

for the rest of the questions, think about what properties a function needs for it to have an inverse.

rich mantle
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Yea what I extremely struggle with is like, how to do the range and domain of those types of questions

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Like part iv as well I don’t know how to do that and I don’t know how to do the range of v)

gilded hinge
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As you may know domain is the values you evaluate the function on, in this case for $f$ the domain is $0 \leq x \leq 2\pi$. The range is the values you can get from evaluating the function over the domain.

upbeat zenithBOT
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Crystopher

gilded hinge
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It may sound hard at first since you may ask: How do I evaluate over every value in the domain if there are infinitely many of these?

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Here's when you use some properties of functions like $f$ and $g$, more specifically they are continuous.

upbeat zenithBOT
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Crystopher

gilded hinge
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since they are continuous we can use the intermediate value theorem.

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So now instead of finding every single evaluation of $f$ to find its range we can just find its lower and upper bound. Then by intermediate value theorem all other values in-between those must also be part of the range.

upbeat zenithBOT
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Crystopher

gilded hinge
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In short, find the lowest (call it $\alpha$) and highest values (call it $\beta$) that $f(x)$ can have in the interval $x\in[0,2\pi]$, then its range is $y \in[\alpha,\beta]$. For this you can use derivatives or properties of trigonometric functions.

upbeat zenithBOT
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Crystopher

rich mantle
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So I sub in 0 and 2pi

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And my range is my values between that?

gilded hinge
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Not necessarily, the ends of the domain are good to study but the highest and lowest value of the function may lie somewhere in-between.

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For instance, you can see that
$f(0)=f(2\pi)=2\sqrt{3}$ but $f(\frac{\pi}{2})= 2$ and $\frac{\pi}{2}>0$

upbeat zenithBOT
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Crystopher

gilded hinge
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Meaning that here $f(0)$ is not the lower bound of the range since there is a smaller value, and there are probably even smaller values than that.

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Crystopher