need help!

[wheat kelp]

try using the identity $\sin^2(x)=1-\cos^2(x)$, so we can simplify fully to $\cos(x)\left(-2\cos(x)-5)=6$ you can see that 0 and $\pi$ are not solutions.

[junior grove]

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[trail wind]

Thank you!

[tawdry hill]

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