#me need halp
20 messages · Page 1 of 1 (latest)
pls
Try to take a look at the successive differences (ie $a_{n+1}- a_{n}$)
CJ_:)
Then try to get a formula for $a_{11}$
CJ_:)
ah okay
Find the common difference of each AP. Then find a formula for the nth term Tn.
a log3 2, log3 4, log3 8, . . .
how does one
i dont log
log?
its a AP of
logv3 2, logv3 4, logv3 8, . . .
tiny 3
but like how is that going up by logv3 2?
If the two is in the exponent, then laws of logarithms let you take it to the outside so you get $$a_{n} =log_{3}n$$
CJ_:)
for this: Ive got the AP but dont know how they got the nth
The nth term is in the form of $a_{n}$ and you plug in n to get that term
CJ_:)