hoary nova
I'm having issues sketching the inequality $(x-4)^2+y^2 \leq 4$. I attempted to rewrite the inequality as $y^2 \leq 4 - (x-4)^2 $ which is $y^2 \leq -(x-6)(x-2)$. I then sketched $x = y^2$ and $ -(x-6)(x-2)$ as seen below. I do not understand why the inequality is equal to the purple circular region.
vale oracleBOT
shy epochBOT
Pen
hoary nova
oh wait
Is it because $(x-4)^2+y^2$ may be thought of some sort circle/ellipse so $(x-4)^2+y^2 \leq 4$ could be thought of all circles/ellipses less than or equal to those with radius 2?
shy epochBOT
Pen
hoary nova
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