#solved
12 messages · Page 1 of 1 (latest)
given: ABDC is a trapezoid, Area of triangle CDE = S, Area of triangle AEB = S+6, DB = 3. find AC's lenght
AC =5
show your work?
i use area to find AB-CD=4
but how
EDB = DBA-EAB and EDB = CDB-CED
EDB = DBA-EAB=> EDB= ( 1/2* 3* AB) - ( S-6)
EDB = CDB-CED => EDB = ( 1/2 3CD) -S
EDB=EDB=> 1/2 3 AB -6= 1/2 3 CD
divide both sides for 3/2 you will have AB -CD=4
oh my god i understand it now tysm