why is -2(3)^(n+1) - 4n(3)^(n+1) equal to 2(3)^(n+1) - 4n(3)^(n+1) - 4(3)^(n+1)? | Mathematics | Page 1

feral oar Apr 9, 2024, 10:19 PM

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I can't understand why the two expressions are equal.

frail violetBOT Apr 9, 2024, 10:19 PM

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feral oar Apr 9, 2024, 10:21 PM

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-2(3)^(n+1) - 4n(3)^(n+1)
2(3)^(n+1) - 4n(3)^(n+1) - 4(3)^(n+1)

turbid tartan Apr 9, 2024, 10:44 PM

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well, 4(3)^(n+1) = 22(3)^(n+1) so if we calculate 2(3)^(n+1)-22(3)^(n+1) we get -2(3)^(n+1)

feral oar Apr 9, 2024, 10:58 PM

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Oh

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Okay, I never would have thought to do that

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Thanks for the help, it makes sense now

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.solved

#why is -2(3)^(n+1) - 4n(3)^(n+1) equal to 2(3)^(n+1) - 4n(3)^(n+1) - 4(3)^(n+1)?