help pls

[empty meteor]

Oh

Wow

Calc 3

No clue

[late maple]

Some prefer doing f(x)/g(x) as f(x)g(x)^-1 and then applying the product/chain rule.

You could also set f(x)/g(x) = z then doing ln(z) = ln(f(x)) - ln(g(x)) and then differentiating

Then solve for z’ which is your answer