#Rotation matrices global to local space

4 messages · Page 1 of 1 (latest)

sudden shoalBOT
golden void
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To find matrix ( A' ) such that ( A'B = C ), where ( A ), ( A' ), ( B ), and ( C ) are matrices, you can use matrix algebra. Given that ( A'B = C ), we want to solve for ( A' ).

First, let's express the equation ( A'B = C ) in terms of ( A' ):
[ A' = (A'B)B^{-1} ]

Here, ( B^{-1} ) denotes the inverse of matrix ( B ), assuming ( B ) is invertible.

Now, let's substitute the given information ( A'B = C ) into the expression for ( A' ):
[ A' = CB^{-1} ]

So, ( A' ) is equal to ( CB^{-1} ). This is the matrix ( A' ) that satisfies the equation ( A'B = C ).

lean oakBOT
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bodhisattv

golden void
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no, how could you find a transformation that maps to multiple reference frames?