Simple Geometry Question

[fathom crag]

Thats a square and Area of I equal to Area of II and Areaa of III

[rich needle]

It appears to be a square, such that Total Area (of square) = I + II + III

Can you define the area relationships for each area?

Area of I = 1/2 bh = 1/2 a(a+b) = (a^2 + ab)/2

Area of III = 1/2 bh = 1/2 d(a+b) = (ad + bd)/2

For II, try dividing it into two separate triangles .... like this to make IIa and IIb

So now Area II = IIa + II b = 1/2 b(a+b) + 1/2 c (*see below for hypot length)

*where the hypot length is expressed in pythroean theorm: hypot^2 = b^2 + (a+b)^2

Also, there's the overall area expression: (a+b)^2 = Area I + Area II + Area III

So after a big mess, I don't know what you want to do with all that as I can't read german lol

[fathom crag]

Thank you thats enough

[coral berry]

.solved