probability of two union events | Mathematics | Page 1

proud archBOT Mar 13, 2024, 2:15 AM

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leaden kettle Mar 13, 2024, 2:26 AM

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Probability of getting at least 2 heads [P(s)]= probability of 2 heads[P(A)] + probability of 3 heads [P(B)]

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P(A) = 3/8 ( since 2 heads on toss is coming out to be 3 times)
And P(B) = 1/8 (there's only one outcome with 3 heads)

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So finally your answer comes out to be P(s) = 3/8+1/8 = 4/8 = 1/2

radiant temple Mar 13, 2024, 5:01 AM

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okay, thank you very much!!

nocturne kraken Mar 13, 2024, 11:55 AM

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.solved

#probability of two union events