#why is this not ududv?
2 messages · Page 1 of 1 (latest)
2 messages · Page 1 of 1 (latest)
Essentially I thought you were converting to polar with the parametrization <ucosv, usinv, u>. When using polar coordinates, isn't the integral always rdrdtheta, because of the Jacobian? In this case, why is there no ududv, and instead simply the integral of the magnitude of the normal vector times dudv?