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5 messages · Page 1 of 1 (latest)
That answer should be correct, by using sine's law.
for the area you can find angle ABC = 180-112-50 = 18.
Then use the sine area formula, which gives
$$\frac{5 \cdot |BC| \cdot \sin{18}^{\circ}}{2}$$
Crystopher
you have found $|BC|$ in the previous part of the exercise.
Crystopher