yes i need help

[sinful nimbus]

For (a), your discriminant will be positive

since this graph has a minimum value, a is negative but since its y-intercept is positive, c is positive

b² is always positive so b²-4ac is also positive

the negative value in a cancels out the negative sign before 4ac

Oh and for (b), it doesnt matter whether b is positive or negative

since b² is always positive

And since the graph clearly cuts the x-axis at two distinct points, both roots of this equation are real

hence d must be positive

Hope that helped