Use sine rule in triangle KTL to show that TL = 50sin47/sin15 | Mathematics | Page 1

frosty kayakBOT Mar 2, 2024, 4:50 AM

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lime lantern Mar 2, 2024, 5:02 AM

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sin47=TM/TK, sin62=TM/TL

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angle KTM = 180-47-90º

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= 43º

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angle LTM=180-62-90

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=28º

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angle KTL=43-28

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=15º

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50/(sin15) = TL/(sin47)

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50(sin47)=TL(sin15)

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TL=[50(sin47)]/(sin15)

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therefore, TL = 50sin47 / sin15

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understand?

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and you should improve your writing fr

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@lament cedar

lament cedar Mar 2, 2024, 5:21 AM

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Yea?

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Thanks for the working btw

lime lantern Mar 2, 2024, 5:46 AM

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you post that not for help? -_-

#Use sine rule in triangle KTL to show that TL = 50sin47/sin15