#calculus proof

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short perchBOT
blazing anchor
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in -1<x<0 y=x therefor we have a line. in x=0 since 0 is rational we get 0. so in x=0 y=0 so the graph is still continues. also in 0<x<1 we have irrational numbers so y=x. therefor we have a line of y=x on the range (-1 , 1)

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since limit of f(x) when x approaches 0 from the right and left are equal to the value f(0)