#How do I solve this for Y/P?
85 messages · Page 1 of 1 (latest)
HSF
remember dividing is just multiplication by reciprocal
yes, because we multiplied both sides by P^{-1}
now do you remember exponent rules?
like $a^b a^c = a^{b+c}$
HSF
yes!
now you can simplify that with like 2 extra steps more
hint: remember the 2nd rule
\newline $(a^b)^c=a^{bc}$
HSF
ok so you ended up with T^a * P^-a right?
the exponents (a, -a) are all factors of a
now remember the hint i said above
applies for 2 exponents at once
wait no that part doesn't make sense in this context
but still the earlier hint applies
try taking the ath root
(taking power to the 1/a)
yes
close: remember you have to take root on both sides
also, you did a small typo
Y/P = T^a * P^-a =/= T^a * P ^{1-a}
well you do what Y/P equals, but it's in a slightly messy form
remove the second ath root and you did it
so Y/P = (T/P)^a
oh alright let me see
alright we solved a right?
now we need to solve b
actually
yeah
it has to be 1
so P_(t+1)=P_t
so (1+g(Y/P))=0
yes
given that g(Y/P)=Y/P - c = 0
what do you know about Y/P?
yes!
i'm not sure if it's neccessary on this part
you can just put 1/P = c/Y then multiply numerator x denominator
so what's P in terms of those 2 constants?
and the reciprocal of a fraction is just switching numerator and denominator, so you get
Y/c = P
yeah, i think we solved it
any other questions or nah?
alright
i'm kinda bored now
so sure
wow that's long
it depends on the earlier question, right?
agh wait i don't know how to do economics at all
i'll try to see if i can help a bit, but i'm not sure i can do a lot
alright
wait how did you get that?
shouldn't it be (T/P)^a= c/(1-t)?
yeah
you can multiply both sides by P^a
yeah
it's
$P^a * (\frac{T}{P})^a$
HSF
and the P's cancel out
by exponent rules
T^a
yes
you can take the ath root
wait how did it end up for you?
cause there's a part that may need a little simplifying
yes!
wait 2 small details:
1/(c(1-t)) can be written as (1-t)/c
well as multiplying by (1-t)/c
and 2nd small detail:
you can distribute the root to get the ath root of ((1-t)/c) * T
but yeah that's pretty much it
i saw that the problem used calculus too
so if you wanna ask about that you can
wait imma search up what is per capita income to help
oh i get it now
imma re-read problem
wait i'm getting answers that don't make sense
sorry you gotta get another helper for this, my economics skills suck
i suppose that was all the algebra left