#How do I solve this for Y/P?

85 messages · Page 1 of 1 (latest)

broken boneBOT
candid tinsel
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try divding by P on both sides

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$T^\alpha P^{1-\alpha} P^{-1}$

mystic sealBOT
candid tinsel
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remember dividing is just multiplication by reciprocal

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yes, because we multiplied both sides by P^{-1}

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now do you remember exponent rules?

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like $a^b a^c = a^{b+c}$

mystic sealBOT
candid tinsel
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yes!

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now you can simplify that with like 2 extra steps more

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hint: remember the 2nd rule
\newline $(a^b)^c=a^{bc}$

mystic sealBOT
candid tinsel
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ok so you ended up with T^a * P^-a right?

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the exponents (a, -a) are all factors of a

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now remember the hint i said above

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applies for 2 exponents at once

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wait no that part doesn't make sense in this context

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but still the earlier hint applies

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try taking the ath root

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(taking power to the 1/a)

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yes

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close: remember you have to take root on both sides

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also, you did a small typo

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Y/P = T^a * P^-a =/= T^a * P ^{1-a}

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well you do what Y/P equals, but it's in a slightly messy form

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remove the second ath root and you did it

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so Y/P = (T/P)^a

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oh alright let me see

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alright we solved a right?

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now we need to solve b

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actually

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yeah

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it has to be 1

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so P_(t+1)=P_t

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so (1+g(Y/P))=0

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yes

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given that g(Y/P)=Y/P - c = 0

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what do you know about Y/P?

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yes!

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i'm not sure if it's neccessary on this part

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you can just put 1/P = c/Y then multiply numerator x denominator

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so what's P in terms of those 2 constants?

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and the reciprocal of a fraction is just switching numerator and denominator, so you get

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Y/c = P

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yeah, i think we solved it

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any other questions or nah?

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alright

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i'm kinda bored now

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so sure

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wow that's long

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it depends on the earlier question, right?

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agh wait i don't know how to do economics at all

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i'll try to see if i can help a bit, but i'm not sure i can do a lot

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alright

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wait how did you get that?

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shouldn't it be (T/P)^a= c/(1-t)?

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yeah

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you can multiply both sides by P^a

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yeah

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it's

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$P^a * (\frac{T}{P})^a$

mystic sealBOT
candid tinsel
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and the P's cancel out

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by exponent rules

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T^a

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yes

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you can take the ath root

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wait how did it end up for you?

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cause there's a part that may need a little simplifying

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yes!

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wait 2 small details:

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1/(c(1-t)) can be written as (1-t)/c

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well as multiplying by (1-t)/c

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and 2nd small detail:

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you can distribute the root to get the ath root of ((1-t)/c) * T

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but yeah that's pretty much it

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i saw that the problem used calculus too

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so if you wanna ask about that you can

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wait imma search up what is per capita income to help

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oh i get it now

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imma re-read problem

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wait i'm getting answers that don't make sense

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sorry you gotta get another helper for this, my economics skills suck

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i suppose that was all the algebra left