#need help with question C

8 messages · Page 1 of 1 (latest)

gentle echo
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Ik it’s graded already but I need to study that question for an exam, anyone know what I did wrong?

plain kestrelBOT
past sky
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ok so to get rid of the brackets, simply multiply the exponent of 3 to each term on both the numerator and denominator. So that would be (6^3*w^27)/(3^3w^18) because we multiplied the exponent of each term by 3. (terms with no exponent visible have an exponent of 1). So then, we can reduce. 6^3 is 216 and 3^3 is 27, and if you divide that it will be 8. Next, we have w^27 and w^18. To reduce, we subtract the two variables and if the exponent in the result isn't negative, we leave it where it's supposed to be. In this case, 27-18 is 9, so the final answer is 8w^9

gentle echo
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i got the answer but that 1 is wrong

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the answer is 8w^9

onyx sun
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6/3 = 2 and w^9/w^6 = w^3 2^3 = 8 (w^3)^3 = w^27 The answer is 8*w^27

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oh man sorry

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(w^3)^3 = w^9