# A square is always positive, therefore, $\left({x^2 - 5x + 6\over x^2 + 5x - 6}\right)^2 \ge 0$ for every real number x (not equal to 1 or -6) Thus, we always have $f(x) >= 3$. The range of f is $[3,+\infty)$
honest acorn
round heath
glass holly
